A CLASS SMD 78M12 LM7812 IC L7812C2T LM7812 Voltage Regulator IC 12V 1.5A 7812 Voltage Regulator IC 3 Pin Leads TO-220 Fixed 12V IC

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SKU: ELPB1017447
Manufacturer: No Brand

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Description: A Class SMD 78M12
A CLASS SMD 78M12 LM7812 IC L7812C2T LM7812 Voltage Regulator IC 12V 1.5A 7812 Voltage Regulator IC 3 Pin Leads TO-220 Fixed 12V IC

The 78M12 positive voltage regulators are identical to the popular 7800 Series devices, except that they are specified for only half the output current. Like the 7800 devices, the 78M00 Series 3-Terminal regulators are intended for local, on-card voltage regulation. Internal current limiting, thermal shutdown circuitry and safe-area compensation for the internal pass transistor combine to make these devices remarkably rugged under most operating conditions. Maximum output current with adequate heatsink is 500mA
Features:
Output current up to 0.5A
No external components required
Internal thermal overload protection
Internal short-circuit current limiting
Output transistor safe-area compensation
Output voltage offered in 4% tolerance
Specification:
Output Type: Fixed
Input Voltage Min: 0V
Input Voltage Max: 35V
Fixed Output Voltage Nom.: 5V
Output Current: 500mA
Linear Regulator Case Style: TO-252
No. of Pins: 3Pins
Operating Temperature Min: -20°C
Operating Temperature Max: 85°C
Product Range: 7805 Voltage Regulators
RoHS Phthalates Compliant: Yes
Brief Description of 7812 Voltage Regulator IC
Voltage regulators are very common in electronic circuits. They provide a constant output voltage for a varied input voltage. In our case the 7805 IC is an iconic regulator IC that finds its application in most of the projects. The name 7805 signifies two meaning, “78” means that it is a positive voltage regulator and “05” means that it provides 5V as output. So our 7805 will provide a +5V output voltage.

The output current of this IC can go up to 1.5A. But, the IC suffers from heavy heat loss hence a Heat sink is recommended for projects that consume more current. For example if the input voltage is 12V and you are consuming 1A, then (12-5) * 1 = 7W. This 7 Watts will be dissipated as heat.

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